A report on the Karpovs & Kortchnois victories over West Orange & Staten Island has been posted on the Garden State League’s blog, along with a recap of the other matches and a few games.
At the The Kenilworthian, Michael Goeller has posted notes to Steve Stoyko’s win over Jose Fernandez.
Radomskyj – Stoyko, GSCL 2009I have annotated the game NM Peter Radomskyj – FM Steve Stoyko, Garden State Chess League 2009 (you can also download the PGN) played Tuesday in the match between West Orange and the Kenilworth Karpovs. Kenilworth won 2.5-1.5 to keep their perfect record at 2-0. See Kenilworth Karpovs Squeeze Orange by Ian Mangion at the Kenilworth Kibitzer blog for details. The Karpovs’ first round match against the Kenilworth Korchnois is analyzed by John Moldovan at the GSCL Blog.
We are not complaining – yet. Two or three of today’s games were quite exciting. But somehow we miss the rush of wins, and a table in which not everyone is in the lead. That will happen tomorrow. It must. Today it was Ponomariov and Ivanchuk who put some token pressure on Aronian and Svidler, but in the end the result was five draws. Round two report.
… we see in this position, where Black had just played …Ng6-f4, attacking White’s queen and rook. How would you assess the situation now?
A) The fork wins for Black;
B) White can get away with perpetual check;
C) He can actually give mate.
The solution is here,
but first ponder over it with a larger version of the diagram.
We are not complaining – yet. Two or three of today’s games were quite exciting. But somehow we miss the rush of win, and a table in which not everyone is in the lead. That will happen tomorrow. It must. Today it was Ponomariov and Ivanchuk who put some token pressure on Aronian and Svidler, but in the end the result was five draws. Round two report.
… we see in this position, where Black had just played …Ng6-f4, attacking White’s queen and rook. How would you assess the situation now?
A) The fork wins for Black;
B) White can get away with perpetual check;
C) He can actually give mate.
The solution is here,
but first ponder over it with a larger version of the diagram.